Find Equation Of Parabola Given Vertex And X Intercepts Calculator

Find Equation of Parabola Given Vertex and X-Intercepts Calculator

Find Equation of Parabola Given Vertex and X-Intercepts Calculator

Parabola Equation Calculator

Enter the vertex (h, k) and two x-intercepts (x1, 0), (x2, 0) to find the equation of the parabola y = a(x-h)² + k.

Results

Enter values to see results
Consistency Check: N/A
Value of 'a': N/A
Equation (Vertex Form): N/A
Equation (Standard Form): N/A
Axis of Symmetry: N/A
Focus: N/A
Directrix: N/A
Formula used: y = a(x-h)² + k, where a = -k / (x1-h)² if h = (x1+x2)/2.
Graph of the parabola with vertex and x-intercepts.

What is a Find Equation of Parabola Given Vertex and X-Intercepts Calculator?

A "find equation of parabola given vertex and x intercepts calculator" is a tool designed to determine the equation of a quadratic function (a parabola) when you know the coordinates of its vertex (h, k) and its x-intercepts (the points where the parabola crosses the x-axis, (x1, 0) and (x2, 0)). Parabolas are U-shaped curves that can open upwards or downwards, and their equations can be expressed in vertex form, y = a(x-h)² + k, or standard form, y = ax² + bx + c.

This calculator is useful for students learning algebra, engineers, physicists, and anyone working with quadratic functions. It verifies if the given vertex and x-intercepts are consistent for a symmetric parabola and then calculates the 'a' coefficient and the full equations. Understanding how to use a find equation of parabola given vertex and x intercepts calculator helps in quickly analyzing and representing quadratic relationships.

Common misconceptions include believing any three points (vertex and two x-intercepts) will always form a standard parabola with a vertical axis of symmetry, without considering the symmetry requirement h = (x1+x2)/2.

Find Equation of Parabola Given Vertex and X-Intercepts Calculator Formula and Mathematical Explanation

The vertex form of a parabola with a vertical axis of symmetry is:

y = a(x - h)² + k

Where:

  • (h, k) are the coordinates of the vertex.
  • 'a' is a non-zero constant that determines the direction (up or down) and width of the parabola.

If the parabola has x-intercepts at (x1, 0) and (x2, 0), these points must satisfy the equation. For a symmetric parabola, the x-coordinate of the vertex 'h' must be the average of the x-intercepts:

h = (x1 + x2) / 2

If this condition holds, we can use one of the x-intercepts, say (x1, 0), and the vertex (h, k) to find 'a':

0 = a(x1 - h)² + k

-k = a(x1 - h)²

If (x1 – h) ≠ 0:

a = -k / (x1 - h)²

Once 'a' is found, we have the equation in vertex form. We can expand it to get the standard form y = ax² + bx + c:

y = a(x² - 2hx + h²) + k

y = ax² - 2ahx + ah² + k

So, b = -2ah and c = ah² + k.

Variables Table

Variable Meaning Unit Typical Range
h x-coordinate of the vertex (length units) Real number
k y-coordinate of the vertex (length units) Real number
x1, x2 x-coordinates of the x-intercepts (length units) Real number
a Coefficient determining parabola's opening and width (units of k / units of h²) Non-zero real number
Variables used in the parabola equation calculation.

Practical Examples (Real-World Use Cases)

Example 1:

Suppose a parabola has its vertex at (2, -8) and x-intercepts at (0, 0) and (4, 0).

  • h = 2, k = -8, x1 = 0, x2 = 4
  • Check symmetry: (0 + 4) / 2 = 2. So h = (x1+x2)/2 is satisfied.
  • Calculate 'a': a = -(-8) / (0 – 2)² = 8 / 4 = 2
  • Vertex form: y = 2(x – 2)² – 8
  • Standard form: y = 2(x² – 4x + 4) – 8 = 2x² – 8x + 8 – 8 = 2x² – 8x

Example 2:

A parabola has a vertex at (-1, 9) and x-intercepts at (-4, 0) and (2, 0).

  • h = -1, k = 9, x1 = -4, x2 = 2
  • Check symmetry: (-4 + 2) / 2 = -1. So h = (x1+x2)/2 is satisfied.
  • Calculate 'a': a = -9 / (-4 – (-1))² = -9 / (-3)² = -9 / 9 = -1
  • Vertex form: y = -1(x – (-1))² + 9 = -(x + 1)² + 9
  • Standard form: y = -(x² + 2x + 1) + 9 = -x² – 2x – 1 + 9 = -x² – 2x + 8

How to Use This Find Equation of Parabola Given Vertex and X-Intercepts Calculator

Using the calculator is straightforward:

  1. Enter Vertex Coordinates: Input the value of 'h' (x-coordinate of the vertex) and 'k' (y-coordinate of the vertex) into the respective fields.
  2. Enter X-Intercepts: Input the values of 'x1' and 'x2' (the x-coordinates of the two x-intercepts) into their fields.
  3. Check Results: The calculator will automatically check if the vertex x-coordinate h = (x1+x2)/2. If consistent, it will calculate 'a', the vertex form, and the standard form of the parabola's equation, along with the focus and directrix. The parabola will also be graphed.
  4. Consistency Message: Pay attention to the "Consistency Check" message. If it indicates an issue, the provided points may not form a standard symmetric parabola with the given vertex.
  5. Reset: Use the "Reset" button to clear inputs to their default values.
  6. Copy Results: Use the "Copy Results" button to copy the calculated values and equations.

The results help you understand the parabola's shape, direction, and position.

Key Factors That Affect Find Equation of Parabola Given Vertex and X-Intercepts Calculator Results

  • Vertex Coordinates (h, k): The position of the vertex directly influences the 'h' and 'k' in the equation y = a(x-h)² + k and also affects the value of 'a' if the intercepts are fixed.
  • X-Intercepts (x1, x2): The locations of the x-intercepts, along with 'k', determine the value of 'a'. The average of x1 and x2 must equal 'h' for consistency.
  • Value of 'a': This coefficient determines if the parabola opens upwards (a > 0) or downwards (a < 0) and how wide or narrow it is. It is derived from h, k, and the intercepts.
  • Symmetry Condition (h = (x1+x2)/2): If this condition is not met, a standard parabola with a vertical axis of symmetry cannot pass through all three given points (vertex and both intercepts). Our find equation of parabola given vertex and x intercepts calculator checks this.
  • Distance between intercepts and vertex: The horizontal distance |x1-h| and vertical distance |k| are crucial for calculating 'a'.
  • Non-zero 'a': If 'k' is zero and x1 or x2 is different from 'h', 'a' would be zero, which is not a parabola. If k=0 and x1=x2=h, 'a' is undefined from this data alone without another point.

Frequently Asked Questions (FAQ)

What if my given vertex and x-intercepts are not consistent (h ≠ (x1+x2)/2)?
The find equation of parabola given vertex and x intercepts calculator will indicate an inconsistency. A standard parabola with a vertical axis of symmetry cannot have its vertex at (h,k) and pass through *both* x1 and x2 if h is not their midpoint. You might have incorrect data, or the parabola might not have a vertical axis of symmetry.
What if the two x-intercepts are the same (x1 = x2)?
If x1 = x2, the parabola touches the x-axis at only one point, meaning the vertex is on the x-axis at that point (h=x1, k=0). If your given 'k' is not 0 or 'h' is not x1, the data is inconsistent.
How is 'a' calculated?
'a' is calculated using the formula a = -k / (x1 – h)², provided h = (x1+x2)/2 and x1 ≠ h.
What does the sign of 'a' mean?
If 'a' > 0, the parabola opens upwards. If 'a' < 0, it opens downwards.
Can I find the equation if only one x-intercept and the vertex are given?
Yes, if you have the vertex (h,k) and one x-intercept (x1, 0), you can find 'a' using a = -k / (x1-h)². The second x-intercept will then be x2 = 2h – x1 due to symmetry.
What is the axis of symmetry?
For a parabola y = a(x-h)² + k, the axis of symmetry is a vertical line x = h.
What are the focus and directrix?
The focus is a point (h, k + 1/(4a)) and the directrix is a line y = k – 1/(4a). The parabola is the set of all points equidistant from the focus and the directrix.
How does the find equation of parabola given vertex and x intercepts calculator handle input errors?
It checks for valid number inputs and the symmetry condition, displaying messages if there are issues.

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