Find Extrema Calculator

Find Extrema Calculator: Locate Maxima and Minima

Find Extrema Calculator

Find Extrema of a Quadratic Function

This calculator finds the extremum (maximum or minimum point) of a quadratic function of the form f(x) = ax2 + bx + c.

The coefficient of x2. Cannot be zero.
The coefficient of x.
The constant term.
Minimum x-value for graph range.
Maximum x-value for graph range.
Results copied to clipboard!

Results

Enter coefficients to see the extremum.
x-coordinate of Extremum (Vertex):
y-coordinate of Extremum (Vertex):
Type of Extremum:
For f(x) = ax2 + bx + c, the x-coordinate of the vertex is -b/(2a). The y-coordinate is f(-b/(2a)). If a > 0, it's a minimum; if a < 0, it's a maximum.
xf(x)
Enter coefficients to populate table.

Table of function values around the extremum.

Graph of f(x) = ax2 + bx + c showing the extremum.

What is Finding Extrema?

Finding extrema involves identifying the points where a function reaches its highest (maximum) or lowest (minimum) values, either globally over its entire domain or locally within a specific interval. For a differentiable function, these extrema often occur at critical points where the derivative is zero or undefined, or at the boundaries of the interval being considered. This find extrema calculator focuses on quadratic functions, where the extremum is found at the vertex of the parabola.

People who study calculus, optimization problems, physics, engineering, economics, and various other fields use the concept of finding extrema to determine optimal conditions, maximum profits, minimum costs, or stable states. Our find extrema calculator simplifies this for quadratic functions.

A common misconception is that every function must have a global maximum or minimum. However, some functions, like linear functions (when 'a' is zero in our case, though we prevent that), may not have a finite global extremum over an unbounded domain.

Find Extrema Formula (for Quadratic Functions) and Mathematical Explanation

For a quadratic function given by the equation:

f(x) = ax2 + bx + c

The graph of this function is a parabola. The extremum (maximum or minimum point) of this parabola is called the vertex.

1. Find the x-coordinate of the vertex: The x-coordinate of the vertex (xv) is found using the formula:

xv = -b / (2a)

This is derived by finding where the derivative f'(x) = 2ax + b equals zero.

2. Find the y-coordinate of the vertex: Substitute the x-coordinate (xv) back into the original function to find the y-coordinate (yv):

yv = f(xv) = a(-b/2a)2 + b(-b/2a) + c = -b2/(4a) + c

3. Determine the type of extremum:

  • If 'a' > 0, the parabola opens upwards, and the vertex is a minimum point.
  • If 'a' < 0, the parabola opens downwards, and the vertex is a maximum point.
  • If 'a' = 0, the function is linear (f(x) = bx + c), not quadratic, and has no such vertex extremum (the calculator prevents a=0).

Our find extrema calculator implements these formulas.

Variables Table

VariableMeaningUnitTypical Range
aCoefficient of x2UnitlessAny non-zero number
bCoefficient of xUnitlessAny real number
cConstant termUnitlessAny real number
xvx-coordinate of the extremumSame as xDepends on a, b
yvy-coordinate of the extremum (value of f(x) at extremum)Same as f(x)Depends on a, b, c

Practical Examples (Real-World Use Cases)

Example 1: Minimizing Cost

A company's cost function is C(x) = 2x2 – 80x + 1000, where x is the number of units produced. To find the number of units that minimize the cost, we use the find extrema calculator with a=2, b=-80, c=1000.

xv = -(-80) / (2 * 2) = 80 / 4 = 20 units.

The minimum cost occurs when 20 units are produced. The minimum cost is C(20) = 2(20)2 – 80(20) + 1000 = 800 – 1600 + 1000 = $200.

Using the calculator with a=2, b=-80, c=1000 gives x=20, y=200, type=Minimum.

Example 2: Maximizing Height of a Projectile

The height H(t) of a projectile launched upwards is given by H(t) = -5t2 + 40t + 2, where t is time in seconds. To find the maximum height, we use the find extrema calculator with a=-5, b=40, c=2.

tv = -(40) / (2 * -5) = -40 / -10 = 4 seconds.

The maximum height is reached at 4 seconds. The maximum height is H(4) = -5(4)2 + 40(4) + 2 = -80 + 160 + 2 = 82 meters.

Using the calculator with a=-5, b=40, c=2 gives x=4, y=82, type=Maximum.

How to Use This Find Extrema Calculator

  1. Enter Coefficient 'a': Input the value for 'a', the coefficient of x2. It cannot be zero.
  2. Enter Coefficient 'b': Input the value for 'b', the coefficient of x.
  3. Enter Coefficient 'c': Input the value for 'c', the constant term.
  4. Enter X Range (Optional): Set the minimum and maximum x-values to define the range for the graph.
  5. View Results: The calculator automatically updates the x and y coordinates of the extremum, its type (minimum or maximum), the table of values, and the graph.
  6. Read the Graph: The graph shows the parabola and highlights the vertex (extremum).
  7. Use Reset: Click "Reset" to return to default values.
  8. Copy Results: Click "Copy Results" to copy the main results and coefficients.

The primary result tells you the location (x, y) and nature (min/max) of the function's turning point. Our find extrema calculator is designed for ease of use.

Key Factors That Affect Extrema Results

For a quadratic function f(x) = ax2 + bx + c, the key factors affecting the extremum are:

  • Coefficient 'a': This determines if the parabola opens upwards (a > 0, minimum) or downwards (a < 0, maximum). The magnitude of 'a' affects how narrow or wide the parabola is, influencing how quickly the function changes around the extremum, but not its x-location.
  • Coefficient 'b': This, along with 'a', determines the x-coordinate of the vertex (-b/2a). Changing 'b' shifts the vertex horizontally.
  • Coefficient 'c': This is the y-intercept and shifts the entire parabola vertically, thus directly affecting the y-coordinate of the extremum.
  • The relationship between 'a' and 'b': The ratio -b/(2a) is crucial for the x-location of the extremum.
  • Domain of interest: While a quadratic has one global extremum, if you are interested in a specific interval [x1, x2], the maximum or minimum within that interval might occur at the boundaries x1 or x2 rather than the vertex if the vertex is outside the interval. Our find extrema calculator focuses on the vertex.
  • Nature of the function: This calculator is specifically for quadratic functions. Other functions (cubic, exponential, etc.) have different methods for finding extrema, often involving derivatives.

Frequently Asked Questions (FAQ)

What is an extremum?
An extremum (plural: extrema) is a point where a function reaches its maximum or minimum value, either globally or locally.
How does this find extrema calculator work?
It calculates the vertex of the parabola represented by f(x) = ax2 + bx + c using the formula x = -b/(2a) and then finds y = f(x).
What if 'a' is zero?
If 'a' is zero, the function is linear (f(x) = bx + c) and has no vertex or quadratic extremum over the entire real line. The calculator will indicate an error if a=0.
Can this calculator find extrema for functions other than quadratic?
No, this specific find extrema calculator is designed only for quadratic functions of the form ax2 + bx + c.
What are critical points?
Critical points are points where the derivative of a function is zero or undefined. For a quadratic function, the only critical point is at the vertex where the derivative is zero.
What is the difference between local and global extrema?
A global extremum is the absolute maximum or minimum value of the function over its entire domain. A local extremum is the maximum or minimum value within a specific neighborhood. For a parabola, the vertex is the global extremum.
How do I know if the vertex is a maximum or minimum?
If the coefficient 'a' is positive, the parabola opens up, and the vertex is a minimum. If 'a' is negative, it opens down, and the vertex is a maximum. Our find extrema calculator tells you this.
Where are extrema used in real life?
Finding extrema is used in optimization problems, like minimizing costs, maximizing profits, finding the maximum height of a projectile, or determining optimal material usage.

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