Find Particular Solution To Differential Equation Calculator

Particular Solution to Differential Equation Calculator

Particular Solution to Differential Equation Calculator

Easily find the particular solution (yp) for second-order linear non-homogeneous differential equations of the form ay" + by' + cy = Aerx using the method of undetermined coefficients with this calculator.

Calculator: ay" + by' + cy = Aerx

Enter the coefficient of y". Cannot be zero for a 2nd order DE.
Enter the coefficient of y'.
Enter the coefficient of y.
Enter the coefficient 'A' from the right-hand side f(x) = Aerx.
Enter the exponent 'r' from the right-hand side f(x) = Aerx.

Results:

Particular Solution yp(x) will appear here.

Characteristic Equation Roots:

Value of ar2+br+c:

Value of 2ar+b:

Form of yp(x):

Undetermined Coefficient(s):

The form of the particular solution yp depends on whether 'r' is a root of the characteristic equation am2+bm+c=0.

What is a Particular Solution to a Differential Equation Calculator?

A particular solution to differential equation calculator is a tool designed to find a specific solution, yp(x), to a non-homogeneous linear differential equation, typically of the form ay" + by' + cy = f(x). Unlike the complementary solution (yc(x)), which solves the homogeneous part (ay" + by' + cy = 0), the particular solution directly addresses the forcing function f(x) on the right-hand side.

This calculator specifically uses the method of undetermined coefficients for cases where f(x) is of the form Aerx. It helps you determine the form of yp(x) and calculate the unknown coefficients based on the values of a, b, c, A, and r.

This calculator is useful for students learning differential equations, engineers, physicists, and anyone working with models described by linear differential equations with constant coefficients and a specific type of forcing function. A common misconception is that the particular solution is the complete solution; however, the general solution is y(x) = yc(x) + yp(x).

Particular Solution Formula and Mathematical Explanation (Method of Undetermined Coefficients for f(x)=Aerx)

We are looking for a particular solution yp(x) to the equation:

ay" + by' + cy = Aerx

The method of undetermined coefficients involves guessing a form for yp(x) based on f(x), substituting it into the differential equation, and solving for the unknown coefficients.

Step 1: Consider the Characteristic Equation

The characteristic equation of the homogeneous part is am2 + bm + c = 0. Its roots determine the form of the complementary solution and influence the form of the particular solution.

Step 2: Guess the Form of yp(x)

Based on f(x) = Aerx, our initial guess for yp(x) is Cerx. However, we need to compare 'r' with the roots of the characteristic equation:

  • Case 1: 'r' is NOT a root of am2 + bm + c = 0. The form of yp(x) is Cerx. Substituting into the DE gives C(ar2 + br + c)erx = Aerx, so C = A / (ar2 + br + c).
  • Case 2: 'r' IS a single root of am2 + bm + c = 0. This means ar2 + br + c = 0, but 2ar + b ≠ 0. The form of yp(x) is Cxerx. Substituting gives C(2ar + b)erx = Aerx, so C = A / (2ar + b).
  • Case 3: 'r' IS a double root of am2 + bm + c = 0. This means ar2 + br + c = 0 and 2ar + b = 0. The form of yp(x) is Cx2erx. Substituting gives 2aCerx = Aerx, so C = A / (2a).

Variables Table:

Variable Meaning Unit Typical Range
a, b, c Coefficients of y", y', and y respectively Varies Real numbers, a ≠ 0
A Coefficient of erx in f(x) Varies Real numbers
r Exponent in erx Varies Real numbers
m Roots of the characteristic equation Varies Real or Complex numbers
C Undetermined coefficient in yp(x) Varies Real number
yp(x) Particular solution Varies Function of x

The particular solution to differential equation calculator automates these checks and calculations.

Practical Examples

Example 1: 'r' is not a root

Consider y" + 3y' + 2y = 6ex. Here a=1, b=3, c=2, A=6, r=1.

Characteristic equation: m2 + 3m + 2 = 0 => (m+1)(m+2)=0 => m=-1, m=-2.

'r'=1 is not a root. So, yp = Cex. ar2+br+c = 1(1)2 + 3(1) + 2 = 1 + 3 + 2 = 6. C = A/6 = 6/6 = 1. So, yp(x) = ex. The calculator would find this.

Example 2: 'r' is a single root

Consider y" – y = 2ex. Here a=1, b=0, c=-1, A=2, r=1.

Characteristic equation: m2 – 1 = 0 => m=1, m=-1.

'r'=1 is a single root. So, yp = Cxex. 2ar+b = 2(1)(1) + 0 = 2. C = A/2 = 2/2 = 1. So, yp(x) = xex. The particular solution to differential equation calculator handles this case.

How to Use This Particular Solution to Differential Equation Calculator

  1. Enter Coefficients a, b, c: Input the coefficients of y", y', and y from your differential equation. Ensure 'a' is not zero.
  2. Enter Forcing Function Parameters A, r: Input the values of 'A' and 'r' from your forcing function f(x) = Aerx.
  3. Calculate: Click the "Calculate" button or just change input values. The calculator automatically updates.
  4. Review Results:
    • Primary Result: Shows the calculated particular solution yp(x).
    • Intermediate Results: Displays the roots of the characteristic equation, the values of ar2+br+c and 2ar+b to determine the case, the form of yp, and the value of the coefficient C.
  5. Reset or Copy: Use "Reset" to go back to default values or "Copy Results" to copy the solution details.

The output helps you understand how the form of yp was chosen and how C was calculated.

Key Factors That Affect Particular Solution Results

  • Coefficients a, b, c: These determine the roots of the characteristic equation, which crucially affects the form of yp if 'r' matches one of the roots.
  • Value of 'r': Whether 'r' is a root of am2+bm+c=0 (and its multiplicity) dictates the form of yp (Cerx, Cxerx, or Cx2erx).
  • Value of 'A': This directly scales the undetermined coefficient C.
  • Roots of the Characteristic Equation: The nature and values of these roots (real distinct, real repeated, complex) determine the complementary solution and are compared with 'r'.
  • Type of Forcing Function f(x): This calculator is for f(x)=Aerx. Different forms of f(x) (like sines, cosines, polynomials) require different initial guesses for yp, as covered by the method of undetermined coefficients.
  • Initial Conditions (for general solution): While not used for yp directly, initial conditions are needed to find the constants in the complementary solution yc when forming the general solution y = yc + yp and solving an initial value problem.

Frequently Asked Questions (FAQ)

What is the difference between a particular solution and a general solution?
A particular solution (yp) is ANY one function that satisfies the non-homogeneous equation ay"+by'+cy=f(x). The general solution is y = yc + yp, where yc is the complementary solution (solving ay"+by'+cy=0) containing arbitrary constants, and yp is one particular solution.
What is the complementary solution?
The complementary solution (yc) is the general solution to the corresponding homogeneous equation ay"+by'+cy=0. It's found using the roots of the characteristic equation.
Why does the form of yp change if 'r' is a root?
If 'r' is a root, the simple guess Cerx would be part of the complementary solution yc, making it satisfy ay"+by'+cy=0, not Aerx. We multiply by x or x2 to get a linearly independent function that can solve the non-homogeneous equation.
Can this calculator handle f(x) = Acos(kx) or Asin(kx)?
This specific calculator is set up for f(x) = Aerx. The method of undetermined coefficients can handle trigonometric f(x), but the form of yp would be Ccos(kx) + Dsin(kx) (or multiplied by x if ik are roots), requiring a different calculation for C and D.
What if 'a' is zero?
If 'a' is zero, the equation becomes a first-order linear differential equation (by'+cy=f(x)), not a second-order one. This calculator assumes a=0.
What if the roots are complex?
The roots of am2+bm+c=0 can be complex. The comparison is still made with 'r'. If 'r' is real, it won't be a complex root unless r=0 and the roots are purely imaginary, but the principle is the same.
How do I find the complete general solution?
First, find the complementary solution yc using the roots from the characteristic equation solver. Then, use this particular solution to differential equation calculator to find yp. The general solution is y(x) = yc(x) + yp(x).
What if f(x) is a sum of terms?
If f(x) = f1(x) + f2(x), you can find a particular solution yp1 for f1(x) and yp2 for f2(x) separately, and then yp = yp1 + yp2 (by the superposition principle).

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